(x^2+2xy+y^2-9)=(y^2-4x^2)

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Solution for (x^2+2xy+y^2-9)=(y^2-4x^2) equation:


Simplifying
(x2 + 2xy + y2 + -9) = (y2 + -4x2)

Reorder the terms:
(-9 + 2xy + x2 + y2) = (y2 + -4x2)

Remove parenthesis around (-9 + 2xy + x2 + y2)
-9 + 2xy + x2 + y2 = (y2 + -4x2)

Reorder the terms:
-9 + 2xy + x2 + y2 = (-4x2 + y2)

Remove parenthesis around (-4x2 + y2)
-9 + 2xy + x2 + y2 = -4x2 + y2

Add '-1y2' to each side of the equation.
-9 + 2xy + x2 + y2 + -1y2 = -4x2 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-9 + 2xy + x2 + 0 = -4x2 + y2 + -1y2
-9 + 2xy + x2 = -4x2 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-9 + 2xy + x2 = -4x2 + 0
-9 + 2xy + x2 = -4x2

Solving
-9 + 2xy + x2 = -4x2

Solving for variable 'x'.

Combine like terms: x2 + 4x2 = 5x2
-9 + 2xy + 5x2 = -4x2 + 4x2

Combine like terms: -4x2 + 4x2 = 0
-9 + 2xy + 5x2 = 0

The solution to this equation could not be determined.

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